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3x^2-5x-11/12=0
We multiply all the terms by the denominator
3x^2*12-5x*12-11=0
Wy multiply elements
36x^2-60x-11=0
a = 36; b = -60; c = -11;
Δ = b2-4ac
Δ = -602-4·36·(-11)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-72}{2*36}=\frac{-12}{72} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+72}{2*36}=\frac{132}{72} =1+5/6 $
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